28y^2+27y-1=0

Solution for 28y^2+27y-1=0 equation:

28y^2+27y-1=0

a = 28; b = 27; c = -1;
Δ = b2-4ac
Δ = 272-4·28·(-1)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-29}{2*28}=\frac{-56}{56}
=-1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+29}{2*28}=\frac{2}{56}
=1/28
$